Optimal. Leaf size=617 \[ -\frac{2 a b \left (-2 a^2 b^2 \sqrt{-c^2}+a^4-b^4 c^2\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (1,\frac{1}{2} (2 m+3),\frac{1}{2} (2 m+5),-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{c f (2 m+3) \left (a^4+b^4 c^2\right )^2}-\frac{2 a b \left (2 a^2 b^2 \sqrt{-c^2}+a^4-b^4 c^2\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (1,\frac{1}{2} (2 m+3),\frac{1}{2} (2 m+5),\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{c f (2 m+3) \left (a^4+b^4 c^2\right )^2}+\frac{\left (-3 a^4 b^2 \sqrt{-c^2}-3 a^2 b^4 c^2+a^6-b^6 \left (-c^2\right )^{3/2}\right ) \tan (e+f x) (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (1,m+1,m+2,-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{2 f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{\left (3 a^4 b^2 \sqrt{-c^2}-3 a^2 b^4 c^2+a^6+b^6 \left (-c^2\right )^{3/2}\right ) \tan (e+f x) (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (1,m+1,m+2,\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{2 f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{4 a^2 b^4 c^2 \tan (e+f x) (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (1,2 (m+1),2 m+3,-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{b^4 c^2 \tan (e+f x) (d \tan (e+f x))^m \text{Hypergeometric2F1}\left (2,2 (m+1),2 m+3,-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{a^2 f (m+1) \left (a^4+b^4 c^2\right )} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 1.57946, antiderivative size = 617, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 7, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.241, Rules used = {3670, 15, 6725, 64, 1831, 1286, 364} \[ -\frac{2 a b \left (-2 a^2 b^2 \sqrt{-c^2}+a^4-b^4 c^2\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m \, _2F_1\left (1,\frac{1}{2} (2 m+3);\frac{1}{2} (2 m+5);-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{c f (2 m+3) \left (a^4+b^4 c^2\right )^2}-\frac{2 a b \left (2 a^2 b^2 \sqrt{-c^2}+a^4-b^4 c^2\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m \, _2F_1\left (1,\frac{1}{2} (2 m+3);\frac{1}{2} (2 m+5);\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{c f (2 m+3) \left (a^4+b^4 c^2\right )^2}+\frac{\left (-3 a^4 b^2 \sqrt{-c^2}-3 a^2 b^4 c^2+a^6-b^6 \left (-c^2\right )^{3/2}\right ) \tan (e+f x) (d \tan (e+f x))^m \, _2F_1\left (1,m+1;m+2;-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{2 f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{\left (3 a^4 b^2 \sqrt{-c^2}-3 a^2 b^4 c^2+a^6+b^6 \left (-c^2\right )^{3/2}\right ) \tan (e+f x) (d \tan (e+f x))^m \, _2F_1\left (1,m+1;m+2;\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right )}{2 f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{4 a^2 b^4 c^2 \tan (e+f x) (d \tan (e+f x))^m \, _2F_1\left (1,2 (m+1);2 m+3;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{f (m+1) \left (a^4+b^4 c^2\right )^2}+\frac{b^4 c^2 \tan (e+f x) (d \tan (e+f x))^m \, _2F_1\left (2,2 (m+1);2 m+3;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{a^2 f (m+1) \left (a^4+b^4 c^2\right )} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 3670
Rule 15
Rule 6725
Rule 64
Rule 1831
Rule 1286
Rule 364
Rubi steps
\begin{align*} \int \frac{(d \tan (e+f x))^m}{\left (a+b \sqrt{c \tan (e+f x)}\right )^2} \, dx &=\frac{c \operatorname{Subst}\left (\int \frac{\left (\frac{d x}{c}\right )^m}{\left (a+b \sqrt{x}\right )^2 \left (c^2+x^2\right )} \, dx,x,c \tan (e+f x)\right )}{f}\\ &=\frac{(2 c) \operatorname{Subst}\left (\int \frac{x \left (\frac{d x^2}{c}\right )^m}{(a+b x)^2 \left (c^2+x^4\right )} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{f}\\ &=\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m}}{(a+b x)^2 \left (c^2+x^4\right )} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{f}\\ &=\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \left (\frac{b^4 x^{1+2 m}}{\left (a^4+b^4 c^2\right ) (a+b x)^2}+\frac{4 a^3 b^4 x^{1+2 m}}{\left (a^4+b^4 c^2\right )^2 (a+b x)}+\frac{x^{1+2 m} \left (a^2 \left (a^4-3 b^4 c^2\right )-2 a b \left (a^4-b^4 c^2\right ) x+b^2 \left (3 a^4-b^4 c^2\right ) x^2-4 a^3 b^3 x^3\right )}{\left (a^4+b^4 c^2\right )^2 \left (c^2+x^4\right )}\right ) \, dx,x,\sqrt{c \tan (e+f x)}\right )}{f}\\ &=\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m} \left (a^2 \left (a^4-3 b^4 c^2\right )-2 a b \left (a^4-b^4 c^2\right ) x+b^2 \left (3 a^4-b^4 c^2\right ) x^2-4 a^3 b^3 x^3\right )}{c^2+x^4} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}+\frac{\left (8 a^3 b^4 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m}}{a+b x} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}+\frac{\left (2 b^4 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m}}{(a+b x)^2} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right ) f}\\ &=\frac{4 a^2 b^4 c^2 \, _2F_1\left (1,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{\left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{b^4 c^2 \, _2F_1\left (2,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{a^2 \left (a^4+b^4 c^2\right ) f (1+m)}+\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \left (\frac{x^{2+2 m} \left (-2 a b \left (a^4-b^4 c^2\right )-4 a^3 b^3 x^2\right )}{c^2+x^4}+\frac{x^{1+2 m} \left (a^2 \left (a^4-3 b^4 c^2\right )+b^2 \left (3 a^4-b^4 c^2\right ) x^2\right )}{c^2+x^4}\right ) \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}\\ &=\frac{4 a^2 b^4 c^2 \, _2F_1\left (1,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{\left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{b^4 c^2 \, _2F_1\left (2,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{a^2 \left (a^4+b^4 c^2\right ) f (1+m)}+\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{2+2 m} \left (-2 a b \left (a^4-b^4 c^2\right )-4 a^3 b^3 x^2\right )}{c^2+x^4} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}+\frac{\left (2 c (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m} \left (a^2 \left (a^4-3 b^4 c^2\right )+b^2 \left (3 a^4-b^4 c^2\right ) x^2\right )}{c^2+x^4} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}\\ &=\frac{4 a^2 b^4 c^2 \, _2F_1\left (1,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{\left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{b^4 c^2 \, _2F_1\left (2,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{a^2 \left (a^4+b^4 c^2\right ) f (1+m)}+\frac{\left (c \left (3 a^4 b^2-b^6 c^2-\frac{a^2 \left (a^4-3 b^4 c^2\right )}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m}}{\sqrt{-c^2}+x^2} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}-\frac{\left (c \left (3 a^4 b^2-b^6 c^2+\frac{a^2 \left (a^4-3 b^4 c^2\right )}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{1+2 m}}{\sqrt{-c^2}-x^2} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}-\frac{\left (2 a b c \left (2 a^2 b^2-\frac{a^4-b^4 c^2}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{2+2 m}}{\sqrt{-c^2}+x^2} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}+\frac{\left (2 a b c \left (2 a^2 b^2+\frac{a^4-b^4 c^2}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{-m} (d \tan (e+f x))^m\right ) \operatorname{Subst}\left (\int \frac{x^{2+2 m}}{\sqrt{-c^2}-x^2} \, dx,x,\sqrt{c \tan (e+f x)}\right )}{\left (a^4+b^4 c^2\right )^2 f}\\ &=\frac{\left (a^6-3 a^2 b^4 c^2-3 a^4 b^2 \sqrt{-c^2}-b^6 \left (-c^2\right )^{3/2}\right ) \, _2F_1\left (1,1+m;2+m;-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right ) \tan (e+f x) (d \tan (e+f x))^m}{2 \left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{\left (a^6-3 a^2 b^4 c^2+3 a^4 b^2 \sqrt{-c^2}+b^6 \left (-c^2\right )^{3/2}\right ) \, _2F_1\left (1,1+m;2+m;\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right ) \tan (e+f x) (d \tan (e+f x))^m}{2 \left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{4 a^2 b^4 c^2 \, _2F_1\left (1,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{\left (a^4+b^4 c^2\right )^2 f (1+m)}+\frac{b^4 c^2 \, _2F_1\left (2,2 (1+m);3+2 m;-\frac{b \sqrt{c \tan (e+f x)}}{a}\right ) \tan (e+f x) (d \tan (e+f x))^m}{a^2 \left (a^4+b^4 c^2\right ) f (1+m)}-\frac{2 a b \left (a^4-b^4 c^2-2 a^2 b^2 \sqrt{-c^2}\right ) \, _2F_1\left (1,\frac{1}{2} (3+2 m);\frac{1}{2} (5+2 m);-\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m}{c \left (a^4+b^4 c^2\right )^2 f (3+2 m)}-\frac{2 a b \left (a^4-b^4 c^2+2 a^2 b^2 \sqrt{-c^2}\right ) \, _2F_1\left (1,\frac{1}{2} (3+2 m);\frac{1}{2} (5+2 m);\frac{c \tan (e+f x)}{\sqrt{-c^2}}\right ) (c \tan (e+f x))^{3/2} (d \tan (e+f x))^m}{c \left (a^4+b^4 c^2\right )^2 f (3+2 m)}\\ \end{align*}
Mathematica [A] time = 5.89128, size = 381, normalized size = 0.62 \[ \frac{c (d \tan (e+f x))^m \left (-\frac{8 a^3 b^3 (c \tan (e+f x))^{5/2} \text{Hypergeometric2F1}\left (1,\frac{1}{4} (2 m+5),\frac{1}{4} (2 m+9),-\tan ^2(e+f x)\right )}{c^2 (2 m+5)}+\frac{b^2 \left (3 a^4-b^4 c^2\right ) \tan ^2(e+f x) \text{Hypergeometric2F1}\left (1,\frac{m+2}{2},\frac{m+4}{2},-\tan ^2(e+f x)\right )}{m+2}+\frac{4 a b \left (b^4 c^2-a^4\right ) (c \tan (e+f x))^{3/2} \text{Hypergeometric2F1}\left (1,\frac{1}{4} (2 m+3),\frac{1}{4} (2 m+7),-\tan ^2(e+f x)\right )}{c^2 (2 m+3)}+\frac{a^2 \left (a^4-3 b^4 c^2\right ) \tan (e+f x) \text{Hypergeometric2F1}\left (1,\frac{m+1}{2},\frac{m+3}{2},-\tan ^2(e+f x)\right )}{c (m+1)}+\frac{b^4 c \left (a^4+b^4 c^2\right ) \tan (e+f x) \text{Hypergeometric2F1}\left (2,2 (m+1),2 m+3,-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{a^2 (m+1)}+\frac{4 a^2 b^4 c \tan (e+f x) \text{Hypergeometric2F1}\left (1,2 (m+1),2 m+3,-\frac{b \sqrt{c \tan (e+f x)}}{a}\right )}{m+1}\right )}{f \left (a^4+b^4 c^2\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.286, size = 0, normalized size = 0. \begin{align*} \int{ \left ( d\tan \left ( fx+e \right ) \right ) ^{m} \left ( a+b\sqrt{c\tan \left ( fx+e \right ) } \right ) ^{-2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{2 \, \sqrt{c \tan \left (f x + e\right )} \left (d \tan \left (f x + e\right )\right )^{m} a b -{\left (b^{2} c \tan \left (f x + e\right ) + a^{2}\right )} \left (d \tan \left (f x + e\right )\right )^{m}}{b^{4} c^{2} \tan \left (f x + e\right )^{2} - 2 \, a^{2} b^{2} c \tan \left (f x + e\right ) + a^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan{\left (e + f x \right )}\right )^{m}}{\left (a + b \sqrt{c \tan{\left (e + f x \right )}}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan \left (f x + e\right )\right )^{m}}{{\left (\sqrt{c \tan \left (f x + e\right )} b + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]